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Salicylic acid (C7H6O3) reacts with acetic anhydride (C4H6O3) to form acetylsalicylic acid (C9H8O4). 2C7H6O3(aq) + C4H6O3(aq) 2C9H8O4(aq) + H2O(l) What is the limiting reactant if 70.0 g of C7H6O3 and 80.0 g of C4H6O3 react? water salicylic acid acetic anhydride acetylsalicylic acid

Answer :

princessesther2011

Answer:

The limiting reactant is salicylic acid.

Explanation:

From the equation of reaction,

1 mole of acetic anhydride (C4H6O3) (102g) reacts with 2 moles of salicylic acid (C7H6O3) (276 g)

80 g of acetic anhydride would react with (80×276/102) = 216.5 g of salicylic acid

216.5 grams of salicylic acid that is required to react with 80 grams of acetic anhydride.

The available mass of salicylic acid is 70 grams which makes salicylic acid the limiting reactant.

Explanation:

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