Answer :
Answer:
The charge is -4.05 C.
Explanation:
Given that,
Electric field = 150 N/C
Suppose What charge would a human with a mass of 62.0 kg have to acquire to overcome his or her weight by the force exerted by the earth's electric field?
We need to calculate the charge
Using formula of electric field
[tex]E=\dfrac{kQ}{r^2}[/tex]
[tex]Q=\dfrac{Er^2}{k}[/tex]
Where, Q=charge
r = distance center of the earth
Put the value into the formula
[tex]Q=\dfrac{150\times(6.38\times10^{6})^2}{9\times10^{9}}[/tex]
[tex]Q=6.78\times10^{5}\ C[/tex]
The electric field is directed in toward the center of the earth.
So, the charge is negative.
We need to calculate the charge
Using formula of electric force
[tex]F=\dfrac{kQq}{r^2}[/tex]
[tex]mg=\dfrac{kQq}{r^2}[/tex]
Put the value into the formula
[tex]62.0\times9.8=\dfrac{9\times10^{9}\times q\times(-6.78\times10^{5})}{(6.38\times10^{6})^2}[/tex]
[tex]q=\dfrac{62.0\times9.8\times(6.38\times10^{6})^2}{9\times10^{9}\times(-6.78\times10^{5})}[/tex]
[tex]q=-4.05\ C[/tex]
Hence, The charge is -4.05 C.