A large insulator sphere of radius R has uniform charge distribution inside, and the total charge is Q. If you cut a small sphere of radius r from the the large sphere, The charge inside your small sphere is equal to:________

Answer :

Answer:

The charge inside the small sphere is [tex]q=\dfrac{Q\times r^3}{R^3}[/tex].

Explanation:

Since, charge is uniformly distributed throughout the sphere.

Therefore, charge density of sphere is,   [tex]\rho=\dfrac{total\ charge}{Volume}=\dfrac{Q}{\dfrac{4}{3}\pi r^3}[/tex].

Charge on sphere of radius r is, [tex]q=\rho\times Volume[/tex]

[tex]q=\rho\times \dfrac{4}{3}\pi r^3[/tex]

Putting value of [tex]\rho[/tex] in above equation.

We get , [tex]q=\dfrac{Q}{\dfrac{4}{3}\pi R^3}\times \dfrac{4}{3}\pi r^3\\\\q=\dfrac{Q\times r^3}{R^3}[/tex]

Hence, this is the required solution.

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