Answer:
6.25×10^6m
Explanation:
Tensile stress of an elastic materials is defined as the ratio of the force exerted on the cable to its cross sectional area. Mathematically,
Tensile stress = Applied Force/Cross sectional area.
Given the weight of the crate = 500kg
Force = mg = 500×10
Force applied = 5000N
Cross sectional area = 80mm²
Since 1mm² = 1×10^-6m²
80mm² = 80×10^-6m²
Tensile stress = 5000/80×10^-6
Tensile stress = 6.25×10^6m
The stress of the cable is therefore 6.25×10^6m
Answer:
The stress= 6.13×10^7N/m^2
Explanation:
Formular for calculating stress=F/A
Where F is force
A is crossectional area of the specimen
But W= mg
W= weight of crate
m= mass of crate
g= acceleration due to gravity
W= 500kg× 9.81=4905N
Stress = 4905N/ 8.0×10^-7m^2
Stress= 6.13×10^7M/m^2
