Answer :
Answer:
It would cost $600 for an advertisement of [tex]\frac{3}{4}[/tex] of a page.
Step-by-step explanation:
Given:
To place an ad in the Harrisonburg newspaper it cost $100 for each 1/8 of a page used.
Now, to find the cost of an advertisement 3/4 of a page.
So, to get the cost we use unitary method:
If, [tex]\frac{1}{8}[/tex] of a page used cost = $100.
Then, 1 page used cost = [tex]100\div \frac{1}{8}[/tex] = [tex]\$800.[/tex]
Thus, [tex]\frac{3}{4}[/tex] of a page used cost = [tex]800\times \frac{3}{4} =\frac{2400}{4}=\$600.[/tex]
Therefore, it would cost $600 for an advertisement of [tex]\frac{3}{4}[/tex] of a page.
Answer: the cost of an advertisement that takes up 3/4 of a page is $600
Step-by-step explanation:
To place an advertisement in the Harrisonburg newspaper it cost $100 for each 1/8 of a page used. This means that the cost of placing an advertisement of 1 page in the Harrisonburg newspaper would be
1/8 × 100 = $800
Therefore, if an advertisement takes up 3/4 of a page, it means that cost of the advertisement would be
3/4 × 800 = 0.75 × 800 = $600