Answer :
Answer:
B. 12.9cm
Step-by-step explanation:
I presume we are asked to find the length of b
[tex]sin\alpha =\frac{opposite}{hypotenuse} \\sin 40^0=\frac{b}{20}\\b=20 X sin 40^0=12.85cm=12.9cm[/tex]
Answer:
B. 12.9cm
Step-by-step explanation:
I presume we are asked to find the length of b
[tex]sin\alpha =\frac{opposite}{hypotenuse} \\sin 40^0=\frac{b}{20}\\b=20 X sin 40^0=12.85cm=12.9cm[/tex]