Hi there!
We know our standard distance formula, [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}=d[/tex]. This is derived from the Pythagorean's theorem, as we can imagine there being a right triangle and finding the hypotenuse for the distance (See the attached graph).
Plugging these points in, we get:
[tex]\sqrt{(-3-5)^2+(2-6)^2}=d[/tex]
[tex]\sqrt{(-8)^2+(-4)^2}=d[/tex]
[tex]\sqrt{64+16}=d[/tex]
[tex]\sqrt{80}=d[/tex]
Thus, we know the answer is E, the square root of 80.
Hope this helps!
