Answer :
Answer : The compartment that has the higher osmotic pressure is, 10 % (m/v) starch solution.
Explanation :
Formula used for osmotic pressure :
[tex]\pi=\frac{nRT}{V}\\\\\pi=\frac{wRT}{MV}[/tex]
where,
= osmotic pressure
V = volume of solution
R = solution constant = 0.0821 L.atm/mole.K
T= temperature of solution = [tex]25^oC=273+25=298K [/tex]
M = molar mass of solute
w = mass of solute
Now we have to determine the osmotic pressure for the following solution.
For 1 % (m/v) starch solution :
1 % (m/v) starch solution means that 1 grams of starch present in 100 mL or 0.1 L of solution.
Molar mass of starch = 692.7 g/mol
[tex]\pi=\frac{(1g)\times (0.0821Latm/moleK)\times (298K)}{(692.7g/mol)\times (0.1L)}[/tex]
[tex]\pi=0.353atm[/tex]
For 10 % (m/v) starch solution :
10 % (m/v) starch solution means that 10 grams of starch present in 100 mL or 0.1 L of solution.
Molar mass of starch = 692.7 g/mol
[tex]\pi=\frac{(10g)\times (0.0821Latm/moleK)\times (298K)}{(692.7g/mol)\times (0.1L)}[/tex]
[tex]\pi=3.53atm[/tex]
From this we conclude that, 10 % (m/v) starch solution has the higher osmotic pressure as compared to 1 % (m/v) starch solution.
Hence, the compartment that has the higher osmotic pressure is, 10 % (m/v) starch solution.