You are riding your bicycle directly away from a stationary source of sound and hear a frequency that is 1.0% lower than the emitted frequency. The speed of sound is 343 m/s. What is your speed

Answer :

Answer:

Explanation:

Given

apparent frequency is 1 % lower than the original frequency

Speed of sound [tex]v=343\ m/s[/tex]

suppose f is the original frequency  

apparent frequency [tex]f'=0.99f[/tex]

using Doppler's formula

[tex]f'=f\cdot \frac{v-v_o}{v+v_s} [/tex]

where  

[tex]f'[/tex]=apparent frequency  

[tex]v[/tex]=velocity of sound in the given media

[tex]v_s[/tex]=velocity of source

[tex]v_o[/tex]=velocity of observer  

[tex]0.99f=f(\dfrac{343-v_o}{v+0})[/tex]

[tex]0.99\times 343=343-v_o[/tex]

[tex]v_o=343\times 0.1[/tex]

[tex]v_o=34.3\ m/s[/tex]

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