Answer :
Option C: 12 units × 8 units are the dimensions of the rectangle
Explanation:
Given that ABCD is a rectangle.
The ordered pairs of the rectangle ABCD are given by
[tex]A(-10,2)[/tex] ,
[tex]B(2,2)[/tex] ,
[tex]C(2,-6)[/tex] and
[tex]D(-10,-6)[/tex]
The graph attached below shows the coordinates of the rectangle ABCD.
We need to find the dimensions of the rectangle.
The dimensions can be determined using the distance formula,
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
The length of AB is given by
[tex]AB=\sqrt{(2+10)^2+(2-2)^2}[/tex]
[tex]=\sqrt{(12)^2}[/tex]
[tex]=12[/tex]
The length of AB is 12 units.
The length of BC is given by
[tex]BC=\sqrt{(2-2)^2+(-6-2)^2}[/tex]
[tex]=\sqrt{(-8)^2}[/tex]
[tex]=8[/tex]
The length of BC is 8 units.
Hence, the dimensions of the rectangle are 12 units × 8 units
Therefore, Option C is the correct answer.

Answer:
12 units × 8 units
Step-by-step explanation:
is the answer