Answer :
The first term a = 1,
Common difference, d: 7 - 1 = 6.
a(n) = a + (n -1)d,
For 30th term. = 1 + (30 -1)*6
= 1 + 29*6 = 1 + 174 = 175
Common difference, d: 7 - 1 = 6.
a(n) = a + (n -1)d,
For 30th term. = 1 + (30 -1)*6
= 1 + 29*6 = 1 + 174 = 175
The 30th term of the given sequence is 175
What is arithmetic sequence ?
Arithmetic sequence is a sequence in which the differences between every consecutive terms are always same.
Example : 3, 5, 7, 9, ..... is an arithmetic sequence where the common difference is 2.
What is the formula of arithmetic sequence ?
Formula of arithmetic sequence is , [tex]a_{n}[/tex] = [tex]a_{1}[/tex] + (n-1)d
where [tex]a_{n}[/tex] = term in the sequence,
[tex]a_{1}[/tex] = [tex]1^{st\\}[/tex] term in the sequence,
d = common difference between terms
What is the required 30th term ?
Given sequence is, 1, 7, 13, 19, ....
Common difference (d) = 7-1=13-7=6
[tex]1^{st\\}[/tex] term in the sequence ([tex]a_{1}[/tex]) = 1
∴ [tex]a_{30}[/tex] = [tex]a_{1}[/tex] + (n-1)d
= 1+(30-1)×6
= 1+29×6
= 1+174
= 175
∴ 30th term is 175.
Learn more about Arithmetic sequence here :
https://brainly.com/question/6561461
#SPJ2