What is the probability that a point chosen at random from AK is on BD?
A.) 1/10
B.) 1/5
C.) 2/5
D.) 3/10

Answer:
B.) 1/5
Step-by-step explanation:
By observation, we can see that between A and K, there are 10 line segments of equal length. (i.e AB, BC, CD,...., IJ, JK)
we can also see that between B and D , there are 2 line segments of equal length (i.e BC and DC)
hence the probability of a random point falling between B and D
= number of line segments between BD / number of line segments between AK
= 2 / 10
= 1/5