The percent data between 6.0 and 6.9 would be 13.59%. Here’s the complete solution for this specific problem.
z = (X - Mean)/SD
z1 = (6 - 5.1)/09 = + 1
z2 = (6.9 - 5.1)/09 = + 2
Required Percent = P(6 < X < 6.9)*100
= P(1 < z < 2)*100
= [P(z < 2) - P(z < 1)]*100
= [0.9772 - 0.8413]*100
= 0.1359*100
= 13.59%
I am hoping that this has answered your query.
The percent data between 6.0 and 6.9 would be 13.59%.
The standard deviation is a measure of the amount of variation or dispersion of a set of values.
Here’s the given data are as follows,
z = (X - Mean)/SD
z₁ = (6 - 5.1)/09 = + 1
z₂ = (6.9 - 5.1)/09 = + 2
Required Percent = P(6 < X < 6.9) X 100
= P(1 < z < 2) X 100
= [P(z < 2) - P(z < 1)] X 100
= [0.9772 - 0.8413] X 100
= 0.1359 X 100
= 13.59%
Thus, the percent data between 6.0 and 6.9 would be 13.59%.
Learn more about Standard deviation from:
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