Answered

When one person shouts at a football game, the sound intensity level at the center of the field is 58.4 dB. When all the people shout together, the intensity level increases to 102 dB. Assuming that each person generates the same sound intensity at the center of the field, how many people are at the game?

Answer :

Khoso123

Answer:

The number of people at game are approximately 22909

Explanation:

Given data

When one person shout [tex]\beta _{1}=58.4dB[/tex]

When n number of person shout together [tex]\beta _{n}=102dB[/tex]

The sound intensity level during one person shout is given by:

[tex]\beta _{1}=10log(\frac{I_{1}}{I_{o}} )\\58.4=10log(\frac{I_{1}}{I_{o}} )\\5.84=log(\frac{I_{1}}{I_{o}} )\\\frac{I_{1}}{I_{o}} =10^{5.84}\\I_{1}=10^{5.84}*I_{o}[/tex]

The sound intensity level during n number of person shout is given by:

[tex]\beta _{n}=10log(\frac{I_{n}}{I_{o}} )\\102=10log(\frac{I_{n}}{I_{o}} )\\10.2=log(\frac{I_{n}}{I_{o}} )\\\frac{I_{n}}{I_{o}}=10^{10.2}\\I_{n}=10^{10.2}*I_{o}[/tex]

Since each person generates same sound intensity and hence total number  of persons can be determined as

 [tex]=\frac{I_{n}}{I_{1}}\\ =\frac{10^{10.2}I_{o}}{10^{5.84}I_{o}} \\=22909[/tex]

Hence

The number of people at game are approximately 22909

Explanation:

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