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An elevator weighing 2,200 lbs is raised one story in 20 seconds. If the distance between stories is 10 feet, the power is developed by the elevator motor is ______ ft × lb/s

The power of the motor required for the elevator is ________ H.P.

Answer :

philaeagles14

Answer: 1100 ft lb/s and 2 H.P

Explanation:

To calculate for the power developed in the elevator motor in ft.lb/s, we multiply the distance and the weight of the elevator and divide the product by the time.

                      Power = (10 ft)(2200 lb) / 20 s = 1100 ft.lb/s

Next, convert the calculated value to HP. 

                             1100 ft.lb/s x (1 HP/ 550 ft.lb/s) = 2 HP

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