Answer :
Answer:
Magnetic field strength in that region is 1.2 T
Explanation:
As we know by the formula of radius of charge moving in external field is given as
[tex]R = \frac{mv}{qB}[/tex]
so we will have
[tex]R = 25 cm[/tex]
[tex]m = 1.6 \times 10^{-27} kg[/tex]
[tex]q = 1.6 \times 10^{-19} C[/tex]
[tex]v = 0.10 \times 3 \times 10^8 m/s[/tex]
now we have
[tex]0.25 = \frac{(1.6 \times 10^{-27})(3\times 10^7)}{(1.6 \times 10^{-19})B}[/tex]
now we have
[tex]B = 1.2 T[/tex]