Answer :
Answer: The molarity of NaOH solution is 0.1325 M.
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Given mass of KHP = 0.411 g
Molar mass of KHP = 204.44 g/mol
Putting values in above equation, we get:
[tex]\text{Moles of KHP}=\frac{0.411g}{204.44g/mol}=0.00201mol[/tex]
The chemical reaction for the reaction of KHP and NaOH follows
[tex]KHC_8H_4O_4(aq.)+NaOH\rightarrow KNaC_8H_4O_4(aq.)+H_2O(l)[/tex]
By Stoichiometry of the reaction:
1 mole of KHP reacts with 1 mole of NaOH
So, 0.0027 moles of KHP will react with = [tex]\frac{1}{1}\times 0.00201=0.00201mol[/tex] of NaOH.
To calculate the molarity of NaOH, we use the equation:
[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}[/tex]
We are given:
Moles of NaOH = 0.00201 moles
Volume of solution = 15.17 mL = 0.01517 L (Conversion factor: 1 L = 1000 mL)
Putting values in above equation, we get:
[tex]\text{Molarity of NaOH }=\frac{0.00201mol}{0.01517L}=0.1325M[/tex]
Hence, the molarity of NaOH solution is 0.1325 M.
The molarity of NaOH solution is 0.1325 M.
To calculate the number of moles, we use the equation:
Number of moles = Given mass / Molar mass
Given mass of KHP = 0.411 g
Molar mass of KHP = 204.44 g/mol
On substituting the values:
Number of moles = 0.411 g / 204.44 g/mol
Number of moles = 0.00201 moles
The chemical reaction for the reaction of KHP and NaOH follows
[tex]KHC_8H_4O_4+NaOH---- > KNaC_8H_4O_4+H_2O[/tex]
By Stoichiometry of the reaction:
1 mole of KHP reacts with 1 mole of NaOH
So, 0.0027 moles of KHP will react with = of NaOH.
Calculation for Molarity:
Molarity = Moles of solute / Volume of solution
Given:
Moles of NaOH = 0.00201 moles
Volume of solution = 15.17 mL = 0.01517 L
On substituting the values:
Molarity = 0.00201 moles / 0.01517 L
Molarity = 0.1325 M
Hence, the molarity of NaOH solution is 0.1325 M.
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