Answer :
Answer:
0.19975
Step-by-step explanation:
P = nCr pʳ qⁿ⁻ʳ
where n is the number of trials,
r is the number of successes,
p is the probability of success,
and q is the probability of failure (1−p).
Given:
n = 11
r = 9
p = 0.7
q = 0.3
Plugging in values:
P = ₁₁C₉ (0.7⁹) (0.3¹¹⁻⁹)
P = 0.19975
Using the principle of binomial probability, the probability that exactly 9 involve multiple vehicle is 0.00053
Probability of single vehicle = 7/10
Probability of multiple vehicle = 1 - (7/10) = 0.3
From the concept of binomial probability :
P(x = x) = nCx * p^x * q^(n-x)
x = 9
n = number of trials = 11
p = probability of success = 0.3
q = 1 - p = 0.7
Therefore, the probability that exactly 9 involve multiple vehicles can be defined as :
P(x = 9) = 11C9 × 0.3^9 × 0.7^2
P(x = 9) = 55 × 0.00000964467
P(x = 9) = 0.00053045685
Therefore, the probability that exactly 9 involve multiple vehicle is 0.00053
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