Answer :
Answer:
957 pounds of pepperoni
Explanation:
In this problem, orders (T) are being taken every 5 weeks while the delivery (L) is approximately 4 weeks. Given a probability of 98 %, we can estimate that the area [F(z)] under the ' z' left side of the normal distribution curve is 0.98. Therefore,
0.98 - 0.50 = 0.48, using the standard normal table, for an area of 0.48, the value is 2.055. Thus, the pounds pepperoni (Q) that will be ordered:
Q = 130(5+4) + 2.055(120) - 460 = 1170 + 246.6 - 460 = 956.6
Approximately 957 pounds of pepperoni.