Answer:
1.77 x [tex]10^{-7}[/tex]Wb
Explanation:
the magnitude of force given by one of the windings is given by "
Ф = BA = ∪nIA
where B is the magnetic field strength inside the solenoid
A is cross-sectiona area of the windings in [tex]m^{2}[/tex] = π x [tex]( \frac{0.75 x 10^{-2} }{2} )^{2}[/tex] = 4.418 x [tex]10^{-5}[/tex][tex]m^{2}[/tex]
∪ is the vacuum permeability = 4π x [tex]10^{-7}[/tex]H/m
n i s given by n is number of turns per m = 160 x 100 per m = 16000/m
Ф = 4 x [tex]10^{-7}[/tex] x 3.142 x 16000 x 0.20 x 4.418 x [tex]10^{-5}[/tex] = 1.77 x [tex]10^{-7}[/tex] Wb
