Answer :
Answer:
a) 200 million dollars
b) 500 million dollars
c) Option A)
[tex]\{x|x \in R, x \geq 0\}[/tex]
Step-by-step explanation:
We are given the following in the question:
[tex]R(x) = \dfrac{1000x^2}{x^2 + 4}[/tex]
where R(x) is the revenue function in millions of dollars and x is the number of years since publication.
a) total revenue at the end of the first year
We put x = 1 in the revenue function
[tex]R(1) = \dfrac{1000(1)^2}{(1)^2 + 4} = 200[/tex]
Thus, the revenue after 1 year is 200 million dollars.
b) total revenue at the end of the second year
We put x = 2 in the revenue function
[tex]R(2) = \dfrac{1000(2)^2}{(2)^2 + 4} = 500[/tex]
Thus, the revenue after 2 year is 500 million dollars.
c) domain of function R
Domain:
It is the values of x for which the function R(x) is defined.
Since,
[tex]x^2 + 4 \neq 0, x \in R[/tex]
Thus, it is a proper function.
The domain is given by
Option A)
[tex]\{x|x \in R, x \geq 0\}[/tex]