Answer :
Answer:
[tex]B=0.27840\ T[/tex]
Explanation:
Given:
mass of the wire, [tex]m=0.05\ kg[/tex]
length of the wire, [tex]L=0.16\ m[/tex]
current in the wire, [tex]I=11\ A[/tex]
Now form the Lorentz force we know that every current carrying wire experiences a magnetic force on it due to the magnetic field components perpendicular to it.
Mathematically given as:
[tex]F=I.L\times B[/tex]
[tex]m.g=I.L\times B[/tex]
here: we nee to balance the gravitational force on the mass.
[tex]B=[/tex] magnetic field
[tex]0.05\times 9.8=11\times 0.16\times B[/tex]
[tex]B=0.27840\ T[/tex]
This magnetic field must be perpendicular to the direction of current in the wire and the these two directional quantities must lie in a plane normal to the direction of gravity according to the Fleming's left hand rule.