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A sample of gas contains 6.25 × 10^-3 mol in a 500.0 mL flask at 265°C. What is the pressure of the gas in kilopascals?

Solve the problem for the pressure of oxygen.
_____kPa

Answer :

The pressure of gas in kilopascals is 55.9

Answer: 55.73 kPa

Explanation:

Using ideal gas law :

[tex]PV=nRT[/tex]

[tex]P=\frac{nRT}{V}[/tex]

P = pressure of the gas=?

V = volume of the gas = 500 ml = 0.5L

T = temperature of the gas =[tex]265^0C=(265+273)K=538K[/tex]

n = number of moles of the gas=[tex]6.25\times 10^{-3}[/tex]

R = gas constant = 0.0821 Latm/moleK

[tex]P=\frac{6.25\times 10^{-3}\times 0.0821\times 538K}{0.5}=0.55atm=55.73kPa[/tex]            

(1 atm =101.325kPa)

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