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A square OABC with the length of a side 6 cm and circle k(O) with a radius 5 cm are given. Which of the lines OA , AB , BC , or AC are secants to the circle k(O)?

Answer :

opudodennis

Answer:

AC and OA

Step-by-step explanation:

-A secant is a  line connecting two points on the circle.

-Given the square OABC of sides 6cm and a circle of r=5cm and  the center of the circle as O, and that the radius of the circle is less than the side of the square:

-The circle passes through OA and OC, but doesn't pass through AB and BC.

Hence, AC and OA are the circle's secants.

A secant is a line that crosses a curve at two or more separate locations. The line AC is a secant to the circle k(O).

What is a secant?

A secant is a line that crosses a curve at two or more separate locations.

As it is given to us that in the square OABC, the length of the side of a square is 6cm and Circle's radius(r) is 5 cm.

As the length of the side square, OABC is 6cm, therefore, OA=AB=BC=CO=6cm

And the length of the radius of the circle k(O) is 5 cm, therefore,

OE = 5 cm,

As We are trying to find the secant line that can cut the circle k(O) at any two points. Now if we look diagram given below, only line AC cuts the circle at two points.

Hence, the line AC is a secant to the circle k(O).

Learn more about Secant:

https://brainly.com/question/10128640

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