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When a certain ideal gas thermometer is placed in water at the triple point, the mercury level in the right arm is 846 mm above the reference mark. Part A How far is the mercury level above the reference mark when this thermometer is placed in boiling water at a location where the atmospheric pressure is 1.00 atm

Answer :

akande212

Answer:

P =1156mmHg

Explanation:

Given

Ptriple = 846mmHg

Ttriple = 273.16K

T = temperature of boiling water = 100°C = (273.16 +100)K = 373.16K

P/Ptriple = T/Ttriple

P = T/Ttriple × Ptriple

P = 373.16/×273.6 × 846

P = 1156mmHg.

The temperature used in this solution is the absolute temperature because the gas thermometer use the absolute temperature scale. On this scale (Kelvin temperature scale) the zero point, Absolute zero is 273.16K.

okpalawalter8

Answer:

  • The mercury level is [tex]1155.68 mm[/tex] above the reference level

Explanation:

Ideal gas obeys the law , [tex]PV = RT[/tex]

When volume remains constant

[tex]\frac{P2}{P1} = \frac{T2}{T1}[/tex]

Temperature of triple point of water is [tex]T1 = 273.16K[/tex]

Temperature of normal boiling point of water is [tex]T2 = 373.15 K[/tex]

therefore,

[tex]P2 = 846 * \frac{373.15}{273.16}\\\\P2 = 1155.68 mm[/tex]

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