Answer :
Answer
The electric flux at the base is,
[tex]\phi_{b}=-\dfrac{\sqrt{3}}{4} E a^{2}[/tex]
Here E is the strength of the electric field, and ais the side.
[tex]\phi_{b}=-\frac{\sqrt{3}}{4}(260 )(0.25)^{2}[/tex]
[tex]=-7.0 N.m^2/C[/tex]
Flux at the base is equal to [tex]=-7.0 N.m^2/C[/tex]
Tetrahedron does not enclose change. So, Total flux is equal to zero.
Now,
[tex]\phi_{b}+3 \phi_{s}=0[/tex]
[tex]\phi_{s}=\frac{-\phi_{s}}{3}[/tex]
[tex]=\frac{7.0}{3}[/tex]
[tex]=2.3\ Nm^2/C[/tex]
Flux on the three side [tex]=2.3\ Nm^2/C[/tex]