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A point charge with charge q1 = 3.40 μC is held stationary at the origin. A second point charge with charge q2 = -4.90 μC moves from the point ( 0.125 m , 0) to the point ( 0.280 m , 0.235 m ). How much work W is done by the electric force on the moving point charge?

Answer :

lublana

Answer:

-0.79 J

Explanation:

We are given that

[tex]q_1=3.4\mu C=3.4\times 10^{-6} C[/tex]

[tex]1\mu C=10^{-6} C[/tex]

[tex]q_2=-4.9\mu C=-4.9\times 10^{-6} C[/tex]

[tex]x_1=0.125,y_1=0[/tex]

[tex]x_2=0.280,y_2=0.235[/tex]

We have to find the work done by the electric force on the moving point charge.

[tex]r_1=\sqrt{x^2_1+y^2_1}=\sqrt{(0.125)^2+0}=0.125[/tex]

[tex]r_2=\sqrt{(0.280)^2+(0.235)^2}=0.366[/tex]

Work done,[tex]W=kq_1q_2(\frac{1}{r_1}-\frac{1}{r_2})[/tex]

Where [tex]k=9\times 10^9[/tex]

Using the formula

[tex]W=9\times 10^9\times 3.4\times 10^{-6}\times(-4.9\times 10^{-6})(\frac{1}{0.125}-\frac{1}{0.366})[/tex]

[tex]W=-0.79 J[/tex]

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