Answer :
Answer:
We will produce 2.87 * 10³ grams CO2 and 1.76 *10³ grams H2O
Explanation:
Step 1: Data given
Mass of C2H6O = 150.0 grams
Molar mass of C2H6O = 46.07 g/mol
Step 2: The balanced equation
C2H6O + 3O2 → 2CO2 + 3H2O
Step 3: Calculate moles C2H6O
Moles C2H6O = mass C2H6O / molar mass C2H6O
Moles C2H6O = 150.0 grams / 46.07 g/mol
Moles C2H6O = 3.256 moles
Step 4: Calculate moles products
For 1 mol C2H6O we need 3 moles O2 to produce 2 moles CO2 and 3 moles H2O
For 3.256 moles C2H6O we'll have 2*3.256 = 6.512 moles CO2
For 3.256 moles C2H6O we'll have 3 * 3.256 = 9.768 moles H2O
Step 5: Calculate mass of products
Mass CO2 = 6.512 moles * 44.01 g/mol = 286.6 grams = 2.87 * 10³ grams
Mass H2O = 9.768 moles * 18.02 g/mol = 176.0 grams = 1.76 *10³ grams
We will produce 2.87 * 10³ grams CO2 and 1.76 *10³ grams H2O