Answer :
We have 8.22 [tex]\times[/tex] 1[tex]0^{24}[/tex] C atoms
We have 4.11 [tex]\times[/tex] 1[tex]0^{24}[/tex] ethanol molecules
Explanation:
Step 1: Data given
Molecular formula of ethanol = [tex]C_{2} H_{6} O[/tex]
Mass of C = 164 grams
Molar mass C = 12.01 g/mol
Step 2: Calculate moles C
Moles C = mass C / molar mass C
Moles C = 164 grams / 12.01 g/mol
Moles C = 13.66 moles
Step 3: Calculate molecules of C
Atoms C = moles C [tex]\times[/tex] number of Avogadro
Atoms C = 13.66 moles [tex]\times[/tex] 6.02 [tex]\times[/tex] 1[tex]0^{23}[/tex] molecules/ mol
Atoms C = 8.22 [tex]\times[/tex] 1[tex]0^{24}[/tex] C atoms
Step 4: Calculate molecules in the sample
For 1 mol [tex]C_{2} H_{6} O[/tex] we have 2 moles C
For 13.66 moles C we have 13.66/ 2 = 6.83 moles [tex]C_{2} H_{6} O[/tex]
Molecules [tex]C_{2} H_{6} O[/tex] = 6.83 moles [tex]\times[/tex] 6.02 [tex]\times[/tex] 1[tex]0^{23}[/tex] = 4.11 [tex]\times[/tex] 1[tex]0^{24}[/tex] molecules.