Answer:
approximately 42.05
Step-by-step explanation:
We know that the distance formula is [tex]\sqrt{(x_{2}-x_{1})^{2} +(y_{2}-y_{1})^{2} }[/tex], so if we use (3,8) as point 2 and (21, -30) as point 1 (note that these are interchangeable), we know that
x₂=3
y₂=8
x₁=21
y₁=-30
Then, we can plug it into the formula to get [tex]\sqrt{(3-21)^{2} +(8-(-30))^{2 }} = \sqrt{18^{2}+38^{2}}=sqrt{1769}= 42.05 (approximately)[/tex]
