Answer :
Answer: [tex]K_p={(p_{O_2})}[/tex]
Explanation:
Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as [tex]K[/tex]
[tex]K_p[/tex] is the constant of a certain reaction at equilibrium for gaseous reactants and products.
For the given chemical reaction:
[tex]MoO_3(s)\rightleftharpoons 2MoO_2(s)+O_2(g)[/tex]
The expression of for above equation follows:
[tex]K_p={(p_{O_2})}[/tex]
As solids do not exert pressure, [tex]MoO_3[/tex] and [tex]MoO_2[/tex] are not involved.
The expression for the equilibrium constant Kp for the following reaction is [tex]K_p = (po_2)[/tex]
Equilibrium constant:
It refers to the ratio of the concentration of products to the concentration of reactants where each raised to the power of their stoichiometric ratios. It is expressed as K.
Since the given expression is
MoO3(s) ↔ 2 MoO2(s) + O2(g)
So, the above expression should be considered for constant kp
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