Answer :
Answer: The number of atoms of oxygen present in given amount of aspartame are [tex]2.99\times 10^{24}[/tex]
Explanation:
We are given:
27.2 % oxygen by mass
This means that 27.2 grams of oxygen is present in 100 grams of aspartame
Applying unitary method:
In 100 grams of aspartame, the mass of oxygen present is 27.2 grams
So, in 292 grams of aspartame, the mass of oxygen present will be = [tex]\frac{27.2}{100}\times 292=79.42g[/tex]
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Given mass of oxygen = 79.42 g
Molar mass of oxygen = 16 g/mol
Putting values in above equation, we get:
[tex]\text{Moles of oxygen}=\frac{79.42g}{16g/mol}=4.964mol[/tex]
According to mole concept:
1 mole of an element contains [tex]6.022\times 10^{23}[/tex] number of atoms
So, in 4.964 moles of oxygen will contain = [tex](4.964\times 6.022\times 10^{23})=2.99\times 10^{24}[/tex] number of atoms
Hence, the number of atoms of oxygen present in given amount of aspartame are [tex]2.99\times 10^{24}[/tex]