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Two-thousand ounces of a radioactive substance are stored in a radioactive container. The amount, in ounces, of the substance that is left after t years can be modeled by the equation y=2000e−0.00043t, where y is the amount of the substance left after t years.Approximately how many years will it take until 50 ounces of this substance remains?

Answer :

Answer:

Approximately 1,933.64 years, it will take until 50 ounce of this substance remains.

Step-by-step explanation:

Given that,

The amount, in ounce, of the substance that is left after t years can be modeled by the equation

[tex]y=2000e^{-0.00043t}[/tex]

To find the time, we put y = 50 ounce in the above equation.

[tex]50=2000e^{-0.00043t}[/tex]

[tex]\Rightarrow\frac{ 50}{2000}=e^{-0.00043t}[/tex]

[tex]\Rightarrow\frac{ 1}{400}=e^{-0.00043t}[/tex]

Taking ln function both sides of the above equation

[tex]\Rightarrow ln|\frac{ 1}{400}|=ln|e^{-0.00043t}|[/tex]

[tex]\Rightarrow ln|{ 1}|-ln|{400}|=ln|e^{-0.00043t}|[/tex]   [ since [tex]ln| \frac ab|= ln|a|- ln| b|[/tex]  ]

[tex]\Rightarrow -ln|{400}|={-0.00043t}[/tex]               [ since [tex]ln|1|=0[/tex] and [tex]e^{ln |a|}=a[/tex]  ]

[tex]\Rightarrow t = \frac{ln|{400}|}{0.00043}[/tex]

      ≈1,933.64 years.

Approximately 1,933.64 years, it will take until 50 ounce of this substance remains.

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