Answer :
128 ml is the voume of the balloon if the temperature of the gas increases to 320.0k.
Explanation:
given that:
T1 (initial temperature) = 300K
V1 ( initial volume) = 120ml
T2 (final temperature) = 320 K
V2 (final volume) = ?
Pressure remained constant throughout the process.
From the equation
[tex]\frac{P1V1}{T1}[/tex] = [tex]\frac{P2V2}{T2}[/tex]
Since pressure is constant the equation will be:
[tex]\frac{V1}{T1}[/tex] = [tex]\frac{V2}{T2}[/tex]
V2 = [tex]\frac{V1 X T2}{T1}[/tex]
Putting the values in the above formula:
V2 = [tex]\frac{120 X 320}{300}[/tex]
= 128 ml
128 ml is the volume of the gas if temperature increases from 3OO K to 320k