Answer :
The answer for the following problem is explained below.
Therefore the volume charge density of a substance (ρ) is 0.04 × [tex]10^{-1}[/tex] C.
Explanation:
Given:
radius (r) =2.1 cm = 2.1 ×[tex]10^{-2}[/tex] m
height (h) =8.8 cm = 8.8 ×[tex]10^{-2}[/tex] m
total charge (q) =6.1×[tex]10^{-7}[/tex] C
To solve:
volume charge density (ρ)
We know;
ρ =q ÷ v
volume of cylinder = π ×r × r × h
volume of cylinder =3.14 × 2.1 × 2.1 ×[tex]10^{-4}[/tex] × 8.8 ×[tex]10^{-2}[/tex]
volume of cylinder (v) = 122.23 ×[tex]10^{-6}[/tex]
ρ =q ÷ v
ρ = 6.1×[tex]10^{-7}[/tex] ÷ 122.23 ×[tex]10^{-6}[/tex]
ρ = 0.04 × [tex]10^{-1}[/tex] C
Therefore the volume charge density of a substance (ρ) is 0.04 × [tex]10^{-1}[/tex] C.