Answer :
Therefore, the magnitude of magnetic field at a distance 1.10cm from the origin is 27.3mT
Explanation:
Given;
Number of turns, N = 1000
Inner radius, r₁ = 1cm
Outer radius, r₂ = 2cm
Current, I = 1.5A
Magnetic field strength, B = ?
The magnetic field inside a tightly wound toroid is given by B = μ₀ NI / 2πr
where,
a < r < b and a and b are the inner and outer radii of the toroid.
The magnetic field of toroid is
[tex]B = \frac{u_oNI}{2\pi r}[/tex]
Substituting the values in the formula:
[tex]B (1.10cm) = \frac{(4\pi X 10^-^7 ) ( 1000)(1.5)}{2\pi (1.10) } \\\\[/tex]
[tex]B (1.10cm) = 27.3mT[/tex]
Therefore, the magnitude of magnetic field at a distance 1.10cm from the origin is 27.3mT