Answer:
[tex]3.14r^2(h-\frac{1}{3}h_1)[/tex]
Step-by-step explanation:
Let h be the cylinders height and r the radius.
-The volume of a cylinder is calculated as:
[tex]V=\pi r^2h[/tex]
-Since the cone is within the cylinder, it has the same radius as the cylinder.
-Let [tex]h_1[/tex]be the height of the cone.
-The area of a cone is calculated as;
[tex]V=\pi r^2 \frac{h}{3}\\\\=\frac{1}{3}\pi r^2h_1[/tex]
The volume of the solid section of the cylinder is calculated by subtracting the cone's volume from the cylinders:
[tex]V=V_{cy}-V_{co}\\\\=\pi r^2h-\frac{1}{3}\pi r^2 h_1, \pi=3.14\\\\=3.14r^2(h-\frac{1}{3}h_1)[/tex]
Hence, the approximate area of the solid portion is [tex]3.14r^2(h-\frac{1}{3}h_1)[/tex]
