Answer :
Answer:
[tex]38.9^{\circ}[/tex]
Explanation:
When a ray of light passes through the interface between two mediums, it undergoes refraction, which means that it bends and it also changes speed.
The angle at which the ray of light bends is given by Snell's Law:
[tex]n_1 sin \theta_1 = n_2 sin \theta_2[/tex]
where
[tex]n_1,n_2[/tex] are the index of refraction of the 1st and 2nd medium
[tex]\theta_1, \theta_2[/tex] are the angle of incidence and angle of refraction, which are the angles between the incident (refracted) ray and the normal to the interface between the mediums
In this problem we have:
[tex]n_1=1.458[/tex] is the index of refraction of quartz
[tex]n_2=1.333[/tex] is the index of refraction of water
[tex]\theta_1=35.0^{\circ}[/tex] is the angle of incidence in quartz
Therefore, we can find the angle of refraction:
[tex]sin \theta_2 = \frac{n_1}{n_2}sin \theta_1 = \frac{1.458}{1.333}sin (35.0^{\circ})=0.627\\\theta_2 = sin^{-1}(0.627)=38.9^{\circ}[/tex]
The angle of refraction required is 38.85°.
Refraction refers to the change in the direction of light as it passes from one medium to another. We have the following information from the question;
- refractive index of fused quartz = 1.458 (n1)
- refractive index of water = 1.333 (n2)
- Angle of incidence in fused quartz = 35.0 (θ1)
Using the formula;
θ2 = n1/n2 sinθ1
θ2 = angle of refraction in quartz
θ2 = 1.458/1.333 × sin35.0
θ2 = 0.6273
sin-1 (0.6273) = 38.85°
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