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A large goose lands in a lake and bobs up and down for a short time. A fisherman notices that the first wave crest created by the goose reaches the shore 8.3 s after the goose first contacts the water. The distance between two wave crests is 90 cm, and in 2.0 s he sees four wave crests hit the shore. How can the fisherman use these observations to determine how far from the shore the goose landed?

Answer :

Answer:

Distance will be equal to 11.21 m

Explanation:

We have given distance between two wave crests [tex]\lambda[/tex]= 90 cm = 0.90 m

Time t = 2 sec

Four waves gives 3 cycle , so n = 3

So time period of wave [tex]T=\frac{t}{n}=\frac{2}{3}=0.666sec[/tex]

So velocity [tex]v=\frac{\lambda }{T}=\frac{0.90}{0.666}=1.351m/sec[/tex]

It is given that first wave crest created by goose reaches shore after 8.3 sec

So distance between shore and goose will be equal to

Distance = velocity ×time = 1.351×8.3 = 11.21 m

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