Answer:
10.989
Step-by-step explanation:
This is an addition problem. We can, first, set up all our decimals in a vertical setup:
₁
[tex]+\left\begin{array}{cccc}4.&3.&5&9\\3.&5&6\\3.&0&7\end{array}\right\\\\[/tex]
_______________
1 0 . 9 8 9
We get 9 for the first row because we are adding 9 + 0.
For the next row, we are adding 5 + 6 + 7.
We can break this up into 5 + 5 + 1 + 7.
Since that's just 10 + 8, our answer is 18. We carry the 1 and write the 8 .
For the third row, we can add 1 + 3 + 5 + 0. This is equivalent to 9 + 0, so our answer will be carrying a leaving a 9 in the open spot.
For our final row, we have a decimal, so we will be placing a dot.
For our numbers, we have + 4 + 3 + 3. This is 6 + 4 + , which is 10.
Since this is our last row, we do not carry, but write the number as it is.
Our answer is 10.989.
