The surface area of the triangular prism is 144 cm²
Explanation:
Given:
Base of the triangle = 4
Height of the triangle = 3
Hypotenuse of the triangle = 5
Length of the prism = 11
Surface area of the rectangular prism = ?
Surface area, A = [tex]ah+bh+ch+\frac{1}{2} \sqrt{-a^4 + 2(ab)^2 + 2(ac)^2 - b^4 + 2(bc)^2 - c^4}[/tex]
On substituting the value, we get:
[tex]A = 4 X 11+ 3X11+5X11+\frac{1}{2} \sqrt{-(4)^2 + 2(4X3)^2 + 2(4X5)^2 - 3^4 + 2(3X5)^2-5^4} \\\\A = 144 cm^2[/tex]
Therefore, the surface area of the triangular prism is 144 cm²