Answer :

dalendrk
[tex]3\sqrt{135}=3\sqrt{9\cdot15}=3\cdot\sqrt9\cdot\sqrt{15}=3\cdot3\cdot\sqrt{15}\\\\=\boxed{9\sqrt{15}}\\\\\if\ \sqrt[3]{135}=\sqrt[3]{27\cdot5}=\sqrt[3]{27}\cdot\sqrt[3]5=\boxed{3\sqrt[3]5}\to[/tex]

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