what is the solution for x^2-4x=?

Answer:
Step-by-step explanation:
[tex]18^{x^{2}+4x+4} = 18^{9x+18}\\[/tex]
Compare the powers
x² + 4x + 4 = 9x + 18
x² + 4x + 4 - 9x -18 = 0
x² -5x -14 = 0
x² -7x + 2x - 2 *7 = 0
x(x-7) + 2(x - 7) = 0
(x-7)(x+2) = 0
x - 7 = 0 or x + 2 = 0
x = 7 or x = -2