A gas has a pressure of 1.34 atm when the temperature is 237K. The gas is then heated until the temperature measures 312K. What will be the new pressure?

Answer :

The answer for the following question is answered below.

  • Therefore the new pressure of the gas is 1.76 atm.

Explanation:

Given:

Initial pressure of the gas = 1.34 atm

Initial temperature of the gas = 273 K

final temperature of the gas = 312 K

To solve:

Final temperature of the gas

We know;

From the ideal gas equation

P × V = n × R × T

So;

from the above equation we can say that

    P ∝ T

     [tex]\frac{P}{T}[/tex] = constant  

     [tex]\frac{P_{1} }{P_{2} }[/tex] = [tex]\frac{T_{1} }{T_{2} }[/tex]

Where;

[tex]P_{1}[/tex] = initial pressure of a gas

[tex]P_{2}[/tex] = final pressure of a gas

[tex]T_{1}[/tex] = initial temperature of a gas

[tex]T_{2}[/tex] = final temperature of  a gas

    [tex]P_{2}[/tex] = [tex]\frac{1.34*312}{237}[/tex]

    [tex]P_{2}[/tex]  = 1.76 atm

Therefore the new pressure of the gas is 1.76 atm.

Other Questions