Answer :
Answer is 8.00 mol.
Explanation;
According to the Avogadro's constant, 1 mole has 6.022 x 10²³ particles.
MgCl₂ formula units = 2.41 × 10²⁴
Hence, moles of MgCl₂ = number of formula units / Avogadro's constant
= 2.41 × 10²⁴ / 6.022 x 10²³ mol⁻¹
= 4.00 mol
MgCl₂ has 1 Mg and 2 Cl atoms. Hence, stoichiometric ratio between MgCl₂ and Cl atom is 1 : 2.
Hence, moles of Cl atoms = moles of MgCl₂ x 2
= 4.00 mol x 2
= 8.00 mol
The total number of moles of Cl atom present in [tex]2.41\times{10^{24}}[/tex] unit of [tex]{\text{MgC}}{{\text{l}}_{\text{2}}}[/tex] is [tex]\boxed{{\text{8}}{\text{.0 moles}}}[/tex] .
Further explanation:
Mole is a measure of the amount of substance. Mole is the relation between the mass of the substance and molar mass of substance. It is defined as the mass of a substance in grams divided by its molar mass (g/mol).
The formula to calculate the number of moles is as follows:
[tex]{\text{Number of moles}}\;=\;\frac{{{\text{Given mass}}\left({\text{g}}\right)}}{{{\text{molar mass}}\left( {{\text{g/mol}}}\right)}}[/tex] ...... (1)
Also, according to Avogadro's number, the number of atoms or molecules present in the 1 mole of a substance is [tex]6.022\times{10^{23}}[/tex] .
This means 1 mole of [tex]{\text{MgC}}{{\text{l}}_{\text{2}}}[/tex] contains [tex]6.022\times{10^{23}}[/tex] formula unit of [tex]{\text{MgC}}{{\text{l}}_{\text{2}}}[/tex] .
[tex]1{\text{ mol}}={\text{6}}{\text{.022}}\times{\text{1}}{{\text{0}}^{23}}{\text{MgC}}{{\text{l}}_2}{\text{ formula unit}}[/tex]
Thus, the number of moles of [tex]{\text{MgC}}{{\text{l}}_{\text{2}}}[/tex] in 1 formula unit of [tex]{\text{MgC}}{{\text{l}}_{\text{2}}}[/tex] is,
[tex]1{\text{ formula unit}}\left({{\text{MgC}}{{\text{l}}_2}}\right)=\frac{1}{{{\text{6}}{\text{.022}}\times{\text{1}}{{\text{0}}^{23}}{\text{ }}}}{\text{mol }}\left({{\text{MgC}}{{\text{l}}_2}}\right)[/tex]
The given formula unit of [tex]{\text{MgC}}{{\text{l}}_{\text{2}}}[/tex] is [tex]2.41\times{10^{24}}[/tex] .
Therefore, number of moles in [tex]2.41\times{10^{24}}[/tex] formula units of [tex]{\text{MgC}}{{\text{l}}_{\text{2}}}[/tex] can be calculated by multiplying number of moles per unit of [tex]{\text{MgC}}{{\text{l}}_{\text{2}}}[/tex] with total number of [tex]{\text{MgC}}{{\text{l}}_{\text{2}}}[/tex] formula units. The calculation for moles of [tex]{\text{MgC}}{{\text{l}}_{\text{2}}}[/tex] is as follows:
[tex]\begin{aligned}{\text{Moles of MgC}}{{\text{l}}_2}&=\left({{\text{number of moles per unit of MgC}}{{\text{l}}_{\text{2}}}} \right)\left({{\text{total number of MgC}}{{\text{l}}_{\text{2}}}{\text{\;}}}\right)\\&=\left( {\frac{1}{{{\text{6}}{\text{.022}}\times{\text{1}}{{\text{0}}^{23}}{\text{ }}}}{\text{mol}}}\right)\left({2.41\times{{10}^{24}}}\right)\\&=0.40\times10{\text{mol}}\\&=4.0\,{\text{mol}}\\\end{aligned}[/tex]
Therefore, the number of moles of [tex]{\text{MgC}}{{\text{l}}_{\text{2}}}[/tex] present in [tex]2.41\times{10^{24}}[/tex] formul units is 4.0 moles.
Since each unit of [tex]{\text{MgC}}{{\text{l}}_{\text{2}}}[/tex] contains 2 unit of Cl atom thus 4.0 moles of [tex]{\text{MgC}}{{\text{l}}_{\text{2}}}[/tex] must contains 8.0 moles of Cl atom.
Learn more:
1. Determine the number of atoms in a molecule of white phosphorous.: https://brainly.com/question/9202946
2. Rank the gases in decreasing order of effusion: https://brainly.com/question/1946297
Answer details:
Grade: Senior school
Subject: Chemistry
Chapter: Mole concept
Keywords: Total number of Cl atom, mgcl2, 2.41x10^24, moles, Avogadro number, number of moles, molar mass, given mass, total number of atoms.