Answer :
Answer : The equilibrium concentration of CO in the reaction is, [tex]8.3\times 10^{-4}M[/tex]
Explanation :
The given chemical reaction is:
[tex]CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)[/tex]
The expression for equilibrium constant is:
[tex]K_c=\frac{[COCl_2]}{[CO][Cl_2]}[/tex]
As we are given:
Concentration of [tex]Cl_2[/tex] at equilibrium = Concentration of [tex]COCl_2[/tex]
So,
[tex]K_c=\frac{[Cl_2]}{[CO][Cl_2]}[/tex]
[tex]K_c=\frac{1}{[CO]}[/tex]
[tex]1.2\times 10^3=\frac{1}{[CO]}[/tex]
[tex][CO]=8.3\times 10^{-4}M[/tex]
Therefore, the equilibrium concentration of CO in the reaction is, [tex]8.3\times 10^{-4}M[/tex]