Answered

A sealed isothermal container initially contains 4 moles of methanol gas, CH3OH. The following reversible reaction occurs: CH3OH (g) D 2 H2 (g) +CO (g) At equilibrium, there were 3 moles of CH3OH in the container. What is the total number of moles of gas present in the container at equilibrium?

Answer :

Answer: The total number of moles of gas present in the container at equilibrium are 6 moles

Explanation:

We are given:

Initial moles of methanol = 4 moles

Equilibrium moles of methanol = 3 moles

The given chemical equation follows:

                        [tex]CH_3OH(g)\rightleftharpoons 2H_2(g)+CO(g)[/tex]

Initial:                     4

At eqllm:               4-x                2x          x

Evaluating the value of 'x':

[tex]\Rightarrow 4-x=3\\\\x=1[/tex]

So, equilibrium moles of hydrogen gas = 2x = 2(1) = 2 moles

Equilibrium moles of carbon monoxide gas = x = 1 mole

Total number of moles of gas = [tex][n_{CH_3OH}+n_{H_2}+n_{CO}]=[3+2+1]=6mol[/tex]

Hence, the total number of moles of gas present in the container at equilibrium are 6 moles

Other Questions