A local elementary school determined that the average number of volunteers for their "Step into Spring" annual fundraiser has been 14 persons on average (per event). After taking additional measures to recruit volunteers this year, they got 28 people to volunteer. Test whether these additional measures increased the number of volunteers at a .05 level of significance.

Answer :

Answer:

There is not enough information to answer this question.

We need to conduct a hypothesis in order to check if the mean for the new year is higher than the mean before, the system of hypothesis would be:

Null hypothesis:[tex]\mu_{A} \leq \mu_{B}[/tex]

Alternative hypothesis:[tex]\mu_{A} > \mu_{B}[/tex]

But as we can see we don't have the sample deviations or sample sizes provided, so for this case we don't have enough info to conclude if we have a significant increase on the mean.

Step-by-step explanation:

There is not enough information to answer this question.

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean for the new year is higher than the mean before, the system of hypothesis would be:

Null hypothesis:[tex]\mu_{A} \leq \mu_{B}[/tex]

Alternative hypothesis:[tex]\mu_{A} > \mu_{B}[/tex]

We don't know information about the population deviations, so for this case is better apply a t test to compare means, and the statistic is given by:

[tex]t=\frac{\bar X_{A}-\bar X_{B}}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{B}}{n_{B}}}}[/tex] (1)

But as we can see we don't have the sample deviations or sample sizes provided, so for this case we don't have enough info to conclude if we have a significant increase on the mean.

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