Answer :
Answer: The mass of zinc chloride produced in the reaction is 54.1 grams
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] .....(1)
- For zinc:
Given mass of zinc = 26 g
Molar mass of zinc = 65.4 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of zinc}=\frac{26g}{65.4g/mol}=0.397mol[/tex]
- For HCl:
Given mass of HCl = 42 g
Molar mass of HCl = 36.5 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of HCl}=\frac{42g}{36.5g/mol}=1.150mol[/tex]
The chemical equation for the reaction of zinc and HCl follows:
[tex]Zn+2HCl\rightarrow ZnCl_2+H_2[/tex]
By Stoichiometry of the reaction:
1 mole of zinc reacts with 2 moles of HCl
So, 0.397 moles of zinc will react with = [tex]\frac{2}{1}\times 0.397=0.794mol[/tex] of HCl
As, given amount of HCl is more than the required amount. So, it is considered as an excess reagent.
Thus, zinc metal is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
1 mole of zinc produces 1 mole of zinc chloride
So, 0.397 moles of zinc will produce = [tex]\frac{1}{1}\times 0.397=0.397moles[/tex] of zinc chloride
Now, calculating the mass of zinc chloride from equation 1, we get:
Molar mass of zinc chloride = 136.3 g/mol
Moles of zinc chloride = 0.397 moles
Putting values in equation 1, we get:
[tex]0.397mol=\frac{\text{Mass of zinc chloride}}{136.3g/mol}\\\\\text{Mass of zinc chloride}=(0.397mol\times 136.3g/mol)=54.1g[/tex]
Hence, the mass of zinc chloride produced in the reaction is 54.1 grams