Answer:
0.98046
Step-by-step explanation:
Given:
Here we are required to find
P(5.48 <X<5.82) and between 5.48 and 5.82 we each z-score given by
z = (x - μ) / σ
So 5.48 we have z = -2.714 and 5.82 we have z = 2.143
Therefore we have the area of interest on the normal distribution chart given by :
P( -2,714 < z < 2.143)
= 1 - P(Z<-2.714) + P(Z > 2.143)
= 1 - P(Z<-2.714) + (1 - P(Z < 2.143))
= 1 - 0.00336 + 1 - 0.98382
= 1 - 0.01954 = 0.98046
Answer:
98.04%
Step-by-step explanation:
We have to first find the probability that it will be rejected, that is:
P (X <5.48 or X> 5.82)
z = x - m / sd
With a mean of 5.67 and standard deviation of 0.07.
so we have to:
z1 = (5.48 - 5.67) /0.07 = -2.71
In this case we look in the normal distribution table and we have that z is 0.0034
z2 = (5.82 - 5.67) /0.07 = 2.14
In this case we look in the normal distribution table and we have that z is 0.9838
Thus:
P (z <-2.71 or z> 2.14) = P (z <-2.71) + P (z> 2.14)
= P (z <-2.71) + 1 - P (z <2.14)
Superseded:
= 0.0034 + 1 - 0.9838
= 0.0196
And it would be the probability of being rejected, to be accepted it would be:
1 - 0.0196 = 0.9804
In other words, the probability of being accepted is 98.04%
